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=-P^2+56P+73
We move all terms to the left:
-(-P^2+56P+73)=0
We get rid of parentheses
P^2-56P-73=0
a = 1; b = -56; c = -73;
Δ = b2-4ac
Δ = -562-4·1·(-73)
Δ = 3428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3428}=\sqrt{4*857}=\sqrt{4}*\sqrt{857}=2\sqrt{857}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-2\sqrt{857}}{2*1}=\frac{56-2\sqrt{857}}{2} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+2\sqrt{857}}{2*1}=\frac{56+2\sqrt{857}}{2} $
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